Question: 11 -
What is the circular convolution of the sequences X1(n)={2,1,2,1} and x2(n)={1,2,3,4}, find using the DFT and IDFT concepts?
-
{14,14,16,16}
-
None of the mentioned
-
{16,16,14,14}
-
{14,16,14,16}
Answer:
{14,16,14,16}
Solution:
Given X1(n)={2,1,2,1}=>X1(k)=[6,0,2,0]
Given x2(n)={1,2,3,4}=>X2(k)=[10,-2+j2,-2,-2-j2]
when we multiply both DFTs we obtain the product
X(k)=X1(k).X2(k)=[60,0,-4,0]
By applying the IDFT to the above sequence, we get
x(n)={14,16,14,16}.
Given X1(n)={2,1,2,1}=>X1(k)=[6,0,2,0]
Given x2(n)={1,2,3,4}=>X2(k)=[10,-2+j2,-2,-2-j2]
when we multiply both DFTs we obtain the product
X(k)=X1(k).X2(k)=[60,0,-4,0]
By applying the IDFT to the above sequence, we get
x(n)={14,16,14,16}.
Question: 12 -
If X(k) is the N-point DFT of a sequence x(n), then what is the DFT of x*(n)?
-
None of the mentioned
-
X(N-k)
-
X*(k)
-
X*(N-k)
Answer:
X*(N-k)
Solution:
Complex conjugate property of DFT, we have if X(k) is the N-point DFT of a sequence x(n), then what is the DFT of x*(n) is X*(N-k).
Complex conjugate property of DFT, we have if X(k) is the N-point DFT of a sequence x(n), then what is the DFT of x*(n) is X*(N-k).
Question: 13 -
If X1(k) and X2(k) are the N-point DFTs of X1(n) and x2(n) respectively, then what is the N-point DFT of x(n)=ax1(n)+bx2(n)?
-
X1(ak)+X2(bk)
-
eakX1(k)+ebkX2(k)
-
aX1(k)+bX2(k)
-
None of the mentioned
Answer:
aX1(k)+bX2(k)
Solution not available.
Question: 14 -
What is the circular convolution of the sequences X1(n)={2,1,2,1} and x2(n)={1,2,3,4}?
-
{2,3,6,4}
-
{14,16,14,16}
-
{14,14,16,16}
-
{16,16,14,14}
Answer:
{14,16,14,16}
Solution:
x(m)= ∑N−1n=0 x1(n) x2(m−n)N
For m=0, x2((-n))4={1,4,3,2}
For m=1, x2((1-n))4={2,1,4,3}
For m=2, x2((2-n))4={3,2,1,4}
For m=3, x2((3-n))4={4,3,2,1}
Now we get x(m)={14,16,14,16}.
x(m)= ∑N−1n=0 x1(n) x2(m−n)N
For m=0, x2((-n))4={1,4,3,2}
For m=1, x2((1-n))4={2,1,4,3}
For m=2, x2((2-n))4={3,2,1,4}
For m=3, x2((3-n))4={4,3,2,1}
Now we get x(m)={14,16,14,16}.
Question: 15 -
The computational procedure for Decimation in frequency algorithm takes
-
Log2 N2 stages
-
Log2 N stages
-
2Log2 N stages
-
None of the above
Answer:
Log2 N stages