Question: 16 -
If x(n)=an, then what is one sided z-transform of x(n+2)?
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(z−2/(1−az−1 ))+ a-1z-1 + a-2
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(z−2/(1−az−1 ))- a-1z-1 + a-2
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(z−2/(1−az−1 ))+ az + a-2
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(z2/(1−az−1 ))- z2 - az
Answer:
(z2/(1−az−1 ))- z2 - az
Solution not available.
Question: 17 -
The several ways to perform an inverse Z transform are 1) Direct computation 2) Long division 3) Partial fraction expansion with table lookup 4) Direct inversio
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All the four are correct
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1, 2 and 3 are correct
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2 and 3 are correct
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1 and 2 are correct
Answer:
All the four are correct
Solution not available.
Question: 18 -
What is the one sided z-transform X+(z) of the signal x(n)={1,2,5↑,7,0,1}?
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z2+2z+5+7z-1+z-3
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5+7z+z3
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5+7z-1+z-3
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z-2+2z-1+5+7z+z3
Answer:
5+7z-1+z-3
Solution:
Since the one sided z-transform is valid only for n>=0, the z-transform of the given signal will be X+(z)= 5+7z-1+z-3.
Since the one sided z-transform is valid only for n>=0, the z-transform of the given signal will be X+(z)= 5+7z-1+z-3.
Question: 19 -
The region of convergence of x/ (1+2x+x2) is
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Positive
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None of these
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Negative
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1
Answer:
Negative
Solution not available.
Question: 20 -
What is the one sided z-transform of x(n)=δ(n-k)?
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zk
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z-k
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1
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0
Answer:
z-k
Solution:
Since the signal x(n)= δ(n-k) is a causal signal i.e., it is defined for n>0 and x(n)=1 at z=k
So, from the definition of one sided z-transform X+(z)=z-k.
Since the signal x(n)= δ(n-k) is a causal signal i.e., it is defined for n>0 and x(n)=1 at z=k
So, from the definition of one sided z-transform X+(z)=z-k.