Question: 41 -
The average of first three numbers is double of the fourth number. If the average of all
the four numbers is 12, find the 4th number
-
18
-
16
-
20
-
48/7
Answer:
48/7
Solution:
(a + b + c) / 3 = 2d
a + b + c = 6d
Also, (a + b + c + d) / 4 = 12
a + b + c + d = 48
6d + d = 48
7d = 48
d = 48 / 7
(a + b + c) / 3 = 2d
a + b + c = 6d
Also, (a + b + c + d) / 4 = 12
a + b + c + d = 48
6d + d = 48
7d = 48
d = 48 / 7
Question: 42 -
The average monthly salary of the employees of a firm is Rs.60 out of the employees 12 officers get an average of Rs.400 per month and the rest an average of Rs. 56 per month , Find the number of employee
-
1202
-
924
-
1032
-
1156
Answer:
1032
Solution:
Actual average salary of 12 officers = 400
Total salary of 12 officers = 400 x 12 = 4800
Average of these 12 officers as a whole =60
Total salary of 12 officers as a whole = 60 x 12 = 720
The total salary of rest = 4800 - 720 = 4080
Difference in average of the rest of officers = 60 - 56 = 4
Rest of the officers ={4080/4}=1020
Total number of employees = 1020 + 12 = 1032
Actual average salary of 12 officers = 400
Total salary of 12 officers = 400 x 12 = 4800
Average of these 12 officers as a whole =60
Total salary of 12 officers as a whole = 60 x 12 = 720
The total salary of rest = 4800 - 720 = 4080
Difference in average of the rest of officers = 60 - 56 = 4
Rest of the officers ={4080/4}=1020
Total number of employees = 1020 + 12 = 1032
Question: 43 -
The mean temperature of Monday to Wednesday was 37C and of Tuesday to Thursday was 34C . If the temperature on Thursday was (4/5) th that of Monday, the temperature on Thursday was?
-
34
-
36
-
37
-
35
Answer:
36
Solution:
M +T+W = 37 x 3 =111 – (1)
T+W+Th = 34x 3= 102
T+W+4/5M = 102 – (2)
(1) – (2) gives
1/5th of temperature on Monday = 111 - 102 =9
Temperature on Monday = 45
Temperature on Thursday = 4/5*45= 36
M +T+W = 37 x 3 =111 – (1)
T+W+Th = 34x 3= 102
T+W+4/5M = 102 – (2)
(1) – (2) gives
1/5th of temperature on Monday = 111 - 102 =9
Temperature on Monday = 45
Temperature on Thursday = 4/5*45= 36
Question: 44 -
The average temperature of the town in the first four days of a month was 58 degrees. The average for the second, third, fourth and fifth days was 60 degrees. If the temperatures of the first and fifth days were in the ratio 7 : 8, then what is the temperature on the fifth day ?
-
65
-
66
-
62
-
64
Answer:
64
Solution:
Sum of temperatures on 1st, 2nd, 3rd and 4th days = (58 * 4) = 232 degrees ... (1)
Sum of temperatures on 2nd, 3rd, 4th and 5th days - (60 * 4) = 240 degrees ....(2)
Subtracting (1) From (2), we get :
Temp, on 5th day - Temp on 1st day = 8 degrees.
Let the temperatures on 1st and 5th days be 7x and 8x degrees respectively.
Then, 8x - 7x = 8 or x = 8.
Temperature on the 5th day = 8x = 64 degrees.
Sum of temperatures on 1st, 2nd, 3rd and 4th days = (58 * 4) = 232 degrees ... (1)
Sum of temperatures on 2nd, 3rd, 4th and 5th days - (60 * 4) = 240 degrees ....(2)
Subtracting (1) From (2), we get :
Temp, on 5th day - Temp on 1st day = 8 degrees.
Let the temperatures on 1st and 5th days be 7x and 8x degrees respectively.
Then, 8x - 7x = 8 or x = 8.
Temperature on the 5th day = 8x = 64 degrees.
Question: 45 -
10 years ago, the average age of a family of 4 members was 24 years. Two children having been born (with age diference of 2 years), the present average age of the family is the same. The present age of the youngest child is :
-
2
-
4
-
1
-
3
Answer:
3
Solution:
Total age of 4 members, 10 years ago = (24 x 4) years = 96 years.
Total age of 4 members now = [96 + (10 x 4)] years = 136 years.
Total age of 6 members now = (24 x 6) years = 144 years.
Sum of the ages of 2 children = (144 - 136) years = 8 years.
Let the age of the younger child be x years.
Then, age of the elder child = (x+2) years.
So, x+(x+2) =8 <=> x=3
Age of younger child = 3 years.
Total age of 4 members, 10 years ago = (24 x 4) years = 96 years.
Total age of 4 members now = [96 + (10 x 4)] years = 136 years.
Total age of 6 members now = (24 x 6) years = 144 years.
Sum of the ages of 2 children = (144 - 136) years = 8 years.
Let the age of the younger child be x years.
Then, age of the elder child = (x+2) years.
So, x+(x+2) =8 <=> x=3
Age of younger child = 3 years.