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Quiz: Mixture & Alligation

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Number of Questions: 50

Question: 46 -

An alloy contains iron, copper and zinc in the ratio of 3:4:2. Another alloy contains copper, zinc and tin in the ratio of 10:5:3. If equal quantities of both alloys are melted, then weight of tin per kg in the new alloy

Options:

  1. 1/14 kg

  2. 1/10 kg

  3. 1/12 kg

  4. 1/8 kg

    5. Answer:

    1/12 kg
    Solution:

    I:C:Z = 3:4:2 (in first alloy) and C:Z:T = 10:5:3
    Equal quantities is taken. So, I:C:Z = 6:8:4 in first alloy and C:Z:T = 10:5:3
    I = 6
    C = 8 + 10 = 18
    Z = 4+5 = 9
    T = 3
    So weight of tin = 3/36 = 1/12

Question: 47 -

A 40 litre mixture contains milk and water in the ratio of 3:2. 20 litres of the mixture is drawn of and filled with pure milk. This operation is repeated one more time. At the end what is the ratio of milk and water in the resulting mixture?

Options:

  1. 5:1

  2. 6:1

  3. 8:1

  4.  9:1

    5. Answer:

     9:1
    Solution:

    milk = 40*3/5 = 24 and water  = 16 litres initially
    milk = 24 – 20*3/5 + 20 = 32 – 20*4/5 + 20 = 36
    water = 16 – 20*2/5 = 8 – 20*1/5 = 4

Question: 48 -

Two vessels contain milk and water in the ratio of 7:3 and 2:3 respectively. Find the ratio in which the contents of both the vessels must be mixed to get a new mixture containing milk and water  in the ratio 3:2.

Options:

  1. 3:1

  2. 3:5

  3.  2:1

  4.  2:3

    5. Answer:

     2:1
    Solution:

    Let the ratio be k:1
    then in first mixture, milk = 7k/10 and water = 3k/10
    and in second mixture, milk = 2/5 and water = 3/5
    [7k/10 + 2/5]/[3k/10 3/5] = 3/2
    K = 2, so ratio will be 2:1

Question: 49 -

How many Kgs of rice A costing rupees 20 per kg must be mixed with 20 kg of rice B costing rupees 32 per kg, so that after selling them at 35 rupees per kg, he gets a profit of 25%.

Options:

  1. 40

  2. 25

  3. 10

  4. 24

    5. Answer:

    10
    Solution:

    by rule of alligation,
    20           32
    …….28………..
    4            8
    So, x = 10

Question: 50 -

8 litres are drawn from a flask containing milk and then filled with water. The operation is performed 3 more times. The ratio of the quantity of milk left and total solution is 81/625. How much milk the flask initially holds?

Options:

  1. 10ltr

  2. 40ltr

  3. 30ltr

  4. 20ltr

    5. Answer:

    20ltr
    Solution:

    let initial quantity be Q, and final quantity be F
    F = Q*(1 – 8/Q)^4
    81/625 = (1-8/Q)^4
    3/5 = 1 – 8/Q
    Q = 20