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Quiz: Mixture & Alligation

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Number of Questions: 50

Question: 16 -

A Container contains ‘X’ Liters of Milk. A thief stole 50 Liters of Milk and replaced it with the same quantity of water. He repeated the same process further two times. And thus Milk in the container is only ‘X-122’ liters. Then what is the quantity of water in the final mixture?

Options:

  1. 124 Liter

  2. 250 Liter

  3. 128 Liter

  4. 122 Liter

    5. Answer:

    122 Liter
    Solution:

    X-122 = X(1-50/X)³
    X = 250 Liter
    Milk = 250-122 = 128
    Water = 122

Question: 17 -

A jar contains ‘x’ liters of Milk, a seller withdraws 25 liter of it and sells it at Rs.20 per liter. He then replaces it water. He repeated the process total three times. Every time while selling he reduces selling price by Rs.2. After this process Milk left in the mixture is only 108 liters so he decided to sell the entire Mixture at Rs. 15 per liter. Then how much profit did he earned if bought Milk at Rs.20 per liter?

Options:

  1.  Rs.100

  2. Rs.70

  3.  Rs.90

  4.  Rs.50

    5. Answer:

    Rs.70
    Solution:

    Seller sells Milk at Rs.20,18 and 16 respectively for three times
    = 25*(20+18+16) = 1350
    108 = x(1-25/100) 3
    x =256 liter
    He sold entire 256 at Rs.15 =256*15 = 3840
    Cost price = 256*20 = 5120
    profit = 5190-5120 = 70

Question: 18 -

‘X’ Liters of the mixture contains Milk and Water in the ratio 4:3. If 13 liters of Water is added then the ratio becomes 1:1. Then what is the final quantity of water in the mixture?

Options:

  1. 52

  2. 56

  3. 39

  4. 72

    5. Answer:

    52
    Solution:

    4x/3x+13 = 1
    x = 13
    Water = 3x+13 = 39+13 = 52

Question: 19 -

In a 250 liter of a mixture of Milk and Water, Water is X%. The milkman sold 50 liters of the mixture and replaced same quantity with water. If the percent of Milk in final mixture is 64%, then what is the percentage of Milk in the initial mixture?

Options:

  1. 40%

  2. 80%

  3. 20%

  4. 50%

    5. Answer:

    80%
    Solution:

    Milk = 250*(100-x/100)
    50 liters replaced then
    250*(100-x/100) – 50*(100-x/100) = 64% of 250
    X = 20%
    Milk = 80%

Question: 20 -

A Jar contains 100 liters of Milk a thief stole 10 liter of Milk and replaced it with water. Next, he stole 20 liter of Milk and replaced it with water. Again he stole 25 liter of Milk and replaced with water. Then what is the quantity of water in the final mixture?

Options:

  1. 55 Liter

  2.  46 Liter

  3. 50 Liter

  4.  54 Liter

    5. Answer:

     46 Liter
    Solution:

    Milk = 100*90/100*80/100*75/100 = 54
    Water = 100-54 = 46