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Quiz: Mixture & Alligation

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Number of Questions: 50

Question: 26 -

From a container of Milk, a thief has stolen 15 liters of milk and replaced it with same quantity of water. He again repeated the same process. Thus in three attempts, the ratio of Milk and water became 343:169. The initial amount of Milk in the container was: 

Options:

  1. 130 litre

  2. 125 litre

  3. 140 litre

  4. 120 litre

    5. Answer:

    120 litre
    Solution:

    Milk(Left) = 343
    Milk(Initial amount) = 512
    343x = 512x(1 – 15/y)3
    (1-15/y) = 7/8
    y = 120 litre

Question: 27 -

A jar was full with Milk. A person used to draw out 20% of the Milk from the jar and replaced it with water. He has repeated the same process 4 times and thus there was only 512 gm of milk left in the jar, the rest part of the jar was filled with the water. The initial amount of milk in the jar was:

Options:

  1.  1.25 kg

  2. 1.40 kg

  3.  1.30 kg

  4.  1.50 kg

    5. Answer:

     1.25 kg
    Solution:

    Shortcut:
    512 = x(1-1/5)4
    x = 1.25 kg

Question: 28 -

From a container of milk, which contains 200 liters of milk, the seller replaces each time with water when he sells 40 liters of milk(or mixture). Every time he sells out only 40 liters of milk(or mixture). After replacing the milk with water 4th time, the total amount of water in the mixture is

Options:

  1.  87.45L

  2. 75.82L

  3.  81.92L

  4.  85.28L

    5. Answer:

     81.92L
    Solution:

    The amount of Milk left after 4 operations  = 200(1-40/100)4
    = 200 *(4/5)4= 200 * 256/625 = 81.92L; Amount of water = 200 – 81.92 = 118.08L

Question: 29 -

The ratio of Solution “A” and Solution “B” in the container is 3:2 when 10 liters of the mixture is taken out and is replaced by the Solution “B”, the ratio become 2:3. The total quantity of the mixture in the container is:

Options:

  1. 45L

  2. 30L

  3. 20L

  4. 25L

    5. Answer:

    30L
    Solution:

    Initial = 3:2 ; After replacement = 2:3
    2/3 = (1 – 10/n)
    n = 30L

Question: 30 -

From a container, 6 liters Solution “A” was drawn out and was replaced by water. Again 6 liters of the mixture was drawn out and was replaced by the water. Thus the quantity of Solution “A” and water in the container after these two operations is 9:16. The quantity of the mixture is:

Options:

  1. 20L

  2. 25L

  3. 35L

  4. 15L

    5. Answer:

    15L
    Solution:

    Quantity of solution “A” = x(1-6/x)²
    Solution “A” : Water = 9 : 16
    Solution “A” : Solution “A” + water = 9:25
    x(1-6/x)²/x = 9/25
    x = 15L