Question: 16 -
What is the largest 4 digit number exactly divisible by 88?
-
9988 -
9900 -
9944
-
9999
Answer:
9944
Solution:
Largest 4 digit number = 9999
9999 ÷ 88 = 113, remainder = 55
Hence largest 4 digit number exactly divisible by 88
= 9999 - 55 = 9944
Largest 4 digit number = 9999
9999 ÷ 88 = 113, remainder = 55
Hence largest 4 digit number exactly divisible by 88
= 9999 - 55 = 9944
Question: 17 -
The sum of three consecutive integers is 102. Find the lowest of the three?
-
33
-
40
-
29
-
53
Answer:
33
Solution:
Three consecutive numbers can be taken as (P - 1), P, (P + 1).
So, (P - 1) + P + (P + 1) = 102
3P = 102 => P = 34.
The lowest of the three = (P - 1) = 34 - 1 = 33.
Three consecutive numbers can be taken as (P - 1), P, (P + 1).
So, (P - 1) + P + (P + 1) = 102
3P = 102 => P = 34.
The lowest of the three = (P - 1) = 34 - 1 = 33.
Question: 18 -
If the number 481x673 is completely divisible by 9, what is the the smallest whole number in place of x?
-
9
-
7
-
3
-
5
Answer:
7
Solution:
Adding all the numbers 4+8+1+x+6+7+3 = 29
2+9 = 11
similarly 1+1 =2
as a the sum of digits in a number should be equal to 9 for the number to be divisible by 9,
so x = 9-2 = 7
Adding all the numbers 4+8+1+x+6+7+3 = 29
2+9 = 11
similarly 1+1 =2
as a the sum of digits in a number should be equal to 9 for the number to be divisible by 9,
so x = 9-2 = 7
Question: 19 -
The sum of the two digits of a number is 10. If the number is subtracted from the number obtained by reversing its digits, the result is 54. Find the number?
-
34
-
12
-
17
-
28
Answer:
28
Solution:
Any two digit number can be written as (10P + Q),
where P is the digit in the tens place and Q is the
digit in the units place.
P + Q = 10 ----- (1)
(10Q + P) - (10P + Q) = 54
9(Q - P) = 54
(Q - P) = 6 ----- (2)
Solve (1) and (2) P = 2 and Q = 8
The required number is = 28
Any two digit number can be written as (10P + Q),
where P is the digit in the tens place and Q is the
digit in the units place.
P + Q = 10 ----- (1)
(10Q + P) - (10P + Q) = 54
9(Q - P) = 54
(Q - P) = 6 ----- (2)
Solve (1) and (2) P = 2 and Q = 8
The required number is = 28
Question: 20 -
How many of the following numbers are divisible by 132? 264, 396, 462, 792, 968, 2178, 5184, 6336
-
3
-
8
-
6
-
4
Answer:
4