Question: 41 -
The speed of a train 150m long is 50kmph. How much time will it take to pass a platform 600m long?
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50 sec
-
54 sec
-
64 sec
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60 sec
Answer:
54 sec
Solution:
Speed =(50 x 5/18) m/sec = 125/9 m/sec
Required Time = 54 sec
Speed =(50 x 5/18) m/sec = 125/9 m/sec
Required Time = 54 sec
Question: 42 -
How much time will a train 171m long take to cross a bridge 229m long, if it is running at a speed of 45kmph?
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35 sec
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32 sec
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30 sec
-
40 sec
Answer:
32 sec
Solution:
Speed = 25/2 m/sec
Required time = 32 sec
Speed = 25/2 m/sec
Required time = 32 sec
Question: 43 -
A 120m long train takes 10 seconds to cross a man standing on a platform. The speed of the train is
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15 m/sec
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20 m/sec
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12 m/sec
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10m/sec
Answer:
12 m/sec
Solution:
Speed = (120/10) m/sec = 12 m/sec
Speed = (120/10) m/sec = 12 m/sec
Question: 44 -
A train passes two persons walking in the same direction in which the train is going. These persons are walking at the rate of 3km/hr and 5km/hr respectively and the train passes them completely in 10 seconds and 11 seconds respectively. The speed of the train is
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28km/hr
-
27km/hr
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25km/hr
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24 km/hr
Answer:
25km/hr
Solution:
Let the length of the train be x km and it's speed be y km/hr
Speed of the train relative to first man =(y-3)km/hr
Speed of the train relative to second man = (y -5)km/hr
=> Y-3 = 360x and 11y -55 =3600x
=> 10y -30 = 3600x and 11y -55 = 3600x
=> 10y -30 = 11y -55
=> y = 25
Therefore, Speed of the train = 25km/hr.
Let the length of the train be x km and it's speed be y km/hr
Speed of the train relative to first man =(y-3)km/hr
Speed of the train relative to second man = (y -5)km/hr
=> Y-3 = 360x and 11y -55 =3600x
=> 10y -30 = 3600x and 11y -55 = 3600x
=> 10y -30 = 11y -55
=> y = 25
Therefore, Speed of the train = 25km/hr.
Question: 45 -
Two stations A and B are 110 kms apart on a straight line. One train starts from A at 7 a.m and travels towards B at 20km per hour speed Another train starts from B at 8 a.m. and travels towards A at a speed of 25 Km per hour at what time will they meet?
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10 a.m
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none of these
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9 a.m
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11 a.m
Answer:
10 a.m
Solution:
Suppose they meet x hrs after 7 a.m
Distance covered by A in x hrs = (20 × x)
Distance covered by B in (x-1) hrs = 25 (x -1) km.
So they meet at 10 a.m.
Suppose they meet x hrs after 7 a.m
Distance covered by A in x hrs = (20 × x)
Distance covered by B in (x-1) hrs = 25 (x -1) km.
So they meet at 10 a.m.