Question: 21 -

A Shopkeeper fixes the marked price of an item 35% above its c.p.The percentage of discount allowed to gain 8% is.

17%

20%

25%

22%

Answer:

20%

Solution:

let C.P=RS 100

Marked price=RS 135

Required gain=8%

so s.p=RS.108

Discount=135-108=27

Discount%=(27/135)*100=20%

Question: 22 -

A women buys an item at RS.1200 and sells it at the loss of 20%.find S.P OF item.

RS.660

RS.860

RS.960

RS.760

Answer:

RS.960

Solution:

Whenever x% loss,

s.p=(100-x)% of c.p

whenever x% profit, it means

s.p=(100+x)% of c.p

so here will be (100-x)% of c.p

=80% of 1200

=(80/100)*1200=960

Question: 23 -

A milkman purchases the milk at Rs. x per litre and sells it at Rs. 2x per litre still he mixes 2 litres water with every 6 litres of milk. Calculate P%?      

60%

166.66%

116%

100%

Answer:

166.66%

Solution:

Let the cost price of 1-liter {6 liters milk)  → C.P = Rs. 62 liters (water) → C.P = Rs. 0→CP = Rs.6 only

8 litre mixture  =>

SP =>  8 x 2 = Rs. 16

Profit % = 16 − 66x100

= 10006

= 166.66%

Question: 24 -

A Scientist mixes 10% water in his solution but he is not content with it so he again mixes 10% more water in mixture.calculate profit% if he sells at cost price:

None of these

16%

17.7%

21%

Answer:

21%

Solution:

let initial quantity of solution=100ltr

after mixing 10% water,quantity of mixture=110*110/100=121 ltr

c.p of 1 ltr solution=RS.1

TOTAL CP=RS.100,S.P=RS.121

PROFIT=121-100=21

Profit%=21*100/100=21%

Question: 25 -

The profit% on 3 bikes are 15%,35%, and 10%. And the ratio of c.p is 5:3:1. also the ratio of bike sold of P,Q AND R is 2:3:5.calculate profit%.

16%

Data inadequate

21%

18%

Answer:

21%

Solution:

5x*2y+3x*3y+x*5y=24xy

Total profit=(5x*2y*15/100)+(3x*3y*35/100)+(x*5y*10/100)

= 515xy/100

=5.15xy

overall profit%=5.15xy*100/24xy         =21.46%