Question: 1 -
If 5 girls can embroider a dress in 9 days, then the number of days taken by 3 girls will be
-
14 days
-
20 days
-
15 days
-
10 days
Answer:
15 days
Solution:
Let no. of days = N
we know,
M1*D1=M2*D2
5 * 9 = 3 * N
N = 5 × 9/3
= 15 days
Let no. of days = N
we know,
M1*D1=M2*D2
5 * 9 = 3 * N
N = 5 × 9/3
= 15 days
Question: 2 -
If 12 men can do a piece of work in 24 days, then in how many days can 18 men do the same work?
-
20
-
16
-
36
-
18
Answer:
16
Solution:
Let no. of days = N
1 work done = 12 × 24
Then, 12 × 24 = 18 × N days
N days = 12 × 24/18 = 16.
Let no. of days = N
1 work done = 12 × 24
Then, 12 × 24 = 18 × N days
N days = 12 × 24/18 = 16.
Question: 3 -
Mahesh and Umesh can complete a work in 10 days and 15 days respectively. Umesh starts the work and after 5 days Mahesh also joins him. In all the work would be completed in ?
-
7 days
-
9 days
-
None of these
-
11 days
Answer:
9 days
Solution:
Umesh's 5 day's work = 5 x (1/15) = 1/3
Remaining work = (1 - 1/3) = 2/3
(1/10 + 1/15) work is done by both in 1 day
∴ 2/3 work is done by both in 6 x (2/3) = 4 days
Hence, the work was completed in 4 + 5 = 9 days.
Umesh's 5 day's work = 5 x (1/15) = 1/3
Remaining work = (1 - 1/3) = 2/3
(1/10 + 1/15) work is done by both in 1 day
∴ 2/3 work is done by both in 6 x (2/3) = 4 days
Hence, the work was completed in 4 + 5 = 9 days.
Question: 4 -
If 8 men or 12 women can do a piece of work in 10 days, then the number of days required by 4 men and 4 women to finish the work is
-
8
-
12
-
14
-
10
Answer:
12
Solution:
Let no. of days = N
8 men = 12 women
1 woman = 8/12 men = 2/3 men
4 women = 2/3 × 4 men = 8/3 men
4 men + 4 women = 4 + 8/3 men = 20/3 men
1 work done = 8 × 10
8 × 10 = 20/3 × Ndays
N days = 8 × 10 × 3/20 = 12 days.
Let no. of days = N
8 men = 12 women
1 woman = 8/12 men = 2/3 men
4 women = 2/3 × 4 men = 8/3 men
4 men + 4 women = 4 + 8/3 men = 20/3 men
1 work done = 8 × 10
8 × 10 = 20/3 × Ndays
N days = 8 × 10 × 3/20 = 12 days.
Question: 5 -
A and B together can plough a field in 10 hours but by himself A requires 15 hours. How long would B take to plough the same field?
-
10 hrs
-
20 hrs
-
30 hrs
-
40 hrs
Answer:
30 hrs
Solution:
If A and B together can do a piece of work in x days and A alone can do the same work in y days,
then B alone can do the same work in x y/ y – x days.
Therefore,
the No. of hours required by B = 10 × 15/ 15 – 10
= 150/5 = 30 hours.
If A and B together can do a piece of work in x days and A alone can do the same work in y days,
then B alone can do the same work in x y/ y – x days.
Therefore,
the No. of hours required by B = 10 × 15/ 15 – 10
= 150/5 = 30 hours.