Question: 6 -
Ram finishes a work in 7 days. Rahim finish the same job in 8 days and Robert in 6 days. They take turns to finish the work. Ram worked on the first day, Rahim on the second day and Robert on the third and then again Ram and so on. Who was working on the last day when work got finished ?
-
Robert
-
Rahim and Robert
-
Rahim
-
Ram
Answer:
Ram
Solution:
Three day work of Ram, Rahim and Robert = 1/7 + 1/8 + 1/6
= (24 + 21 + 28)/168 = 73/168
Their six days work = (2 x 73)/168 = 146/168 = 73/84
Now, its Ram's turn to work on seventh day.
∴ 73/84 + 1/7 = 73 + 12/84 = 85/84 > 1
So, Ram will finish the work before the end of day.
Hence, Ram is working for the last day.
Three day work of Ram, Rahim and Robert = 1/7 + 1/8 + 1/6
= (24 + 21 + 28)/168 = 73/168
Their six days work = (2 x 73)/168 = 146/168 = 73/84
Now, its Ram's turn to work on seventh day.
∴ 73/84 + 1/7 = 73 + 12/84 = 85/84 > 1
So, Ram will finish the work before the end of day.
Hence, Ram is working for the last day.
Question: 7 -
A man is paid ₹ 5 per h for regular working day and ₹ 8 per h overtime. A regular working day has 8 h and a regular week has 5 working days. If he earns ₹ 920 in 4 weeks, then what is the total number of hours that he worked assuming that he was present on all regular working days ?
-
180 h
-
130 h
-
200 h
-
175 h
Answer:
175 h
Solution:
Number of regular hours during 4 weeks = 8 x 5 x 4 = 160
Amount paid for regular working hours = 160 x 5 = ₹ 800
Balance left = (920 - 800) = ₹ 120
So, ₹ 120 is paid for his over time at ₹ 8 per h.
∴ Total number of overtime working hours = 120/8 = 15 h
Total working hours = (160 + 15) = 175 h
Number of regular hours during 4 weeks = 8 x 5 x 4 = 160
Amount paid for regular working hours = 160 x 5 = ₹ 800
Balance left = (920 - 800) = ₹ 120
So, ₹ 120 is paid for his over time at ₹ 8 per h.
∴ Total number of overtime working hours = 120/8 = 15 h
Total working hours = (160 + 15) = 175 h
Question: 8 -
A is thrice efficient as B and C is twice as efficient as B. what is the ratio of number of days taken by A,B and C ,
when they work individually?
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1 : 2 : 3
-
2 : 3 : 6
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3 : 1 : 2
-
2 : 6 : 3
Answer:
2 : 6 : 3
Solution:
A : B : C
Ratio of efficiency 3 : 1 : 2
Ratio of number of days { 1/3 : 1/1 : 1/2 }
or 2 : 6 : 3 [ using Time = 1/ Efficiency ]
A : B : C
Ratio of efficiency 3 : 1 : 2
Ratio of number of days { 1/3 : 1/1 : 1/2 }
or 2 : 6 : 3 [ using Time = 1/ Efficiency ]
Question: 9 -
The efficiency of Romil is twice that of Sanjay and he can finish a work in 4 h less than the time taken by Sanjay.
If both of them work together they can finish the same work in ?
-
4 h
-
8/3 h
-
8 h
-
3 h
Answer:
8/3 h
Solution:
As the efficience of Romil is twice that of Sanjay, Romil, will take x h for completeion of the work, when Sanjay is taking 2x h.
Given, 2x - x = 4
⇒ x = 4
Hence, they take = 1/(1/4 + 1/8) = 8/3 h
As the efficience of Romil is twice that of Sanjay, Romil, will take x h for completeion of the work, when Sanjay is taking 2x h.
Given, 2x - x = 4
⇒ x = 4
Hence, they take = 1/(1/4 + 1/8) = 8/3 h
Question: 10 -
A, B and C working in a garment manufacturing company can do the same assignment in 24, 6 and 12 days, respectively. Working together the assignment will be complete in how many days ?
-
3days
-
3(3/7) days
-
4days
-
4(3/7) days
Answer:
3(3/7) days
Solution:
(A + B + C)' S 1 day's work = (1/24) + (1/6) + (1/12) = 7/24
∴ (A + B + C) can do the entire work in = 24/7
= 3*(3/7) days
(A + B + C)' S 1 day's work = (1/24) + (1/6) + (1/12) = 7/24
∴ (A + B + C) can do the entire work in = 24/7
= 3*(3/7) days