Question: 11 -
Mr. Modi can copy 40 pages in 10 minutes, Mr. Xerox and Mr. Modi both working together can copy 250 In 25 minutes. In how many minutes Mr. Xerox can copy 36 pages?
-
3 minutes
-
12 minutes
-
5 minutes
-
6 minutes
Answer:
6 minutes
Solution:
Efficiency ( per minute) of Mr. Modi = 4 copies/min
Efficiency of Mr.Modi and Mr.Xerox together = 10 pages/min
∴ Efficiency of Mr. Xerox alone = 10 - 4 = 6 pages/min
∴ Mr. Xerox needs 6 min to copy 36 pages.
Efficiency ( per minute) of Mr. Modi = 4 copies/min
Efficiency of Mr.Modi and Mr.Xerox together = 10 pages/min
∴ Efficiency of Mr. Xerox alone = 10 - 4 = 6 pages/min
∴ Mr. Xerox needs 6 min to copy 36 pages.
Question: 12 -
Mr. Prashant has to build a wall 1000 meters long in 50 days. He employs 56 men but at the end of 27 days finds that only 448 meters are built. How many men must be employed so that the work may be finished in time?
-
25
-
58
-
38
-
81
Answer:
25
Solution:
Y = 56 x (27/23) x (552/448)
=81
Extra men required =81-56
=25
Y = 56 x (27/23) x (552/448)
=81
Extra men required =81-56
=25
Question: 13 -
If A and B can do a piece of work in 7.5 days. If B works 1/2 of work and remaining work was completed by A, taking total time of 20 days to complete the work. If b is more efficient then B can do work in how many days?
-
10 days
-
11 days
-
20 days
-
8 days
Answer:
10 days
Solution:
1/A + 1/B = 2/15 or (A+B)/AB= 2/15 ----(i)
(1/2)/(1/A) + (1/2)/(1/B) = 20 or A/2 + B/2 = 20 or A+B= 40 ----(ii)
Substituting A+B= 40 from (ii) in (i), we get AB= 300
Now finding the factors of 300, whose sum is 40, we have 10 and 30
As B is more efficient than A, B can do the work in 10 days.
1/A + 1/B = 2/15 or (A+B)/AB= 2/15 ----(i)
(1/2)/(1/A) + (1/2)/(1/B) = 20 or A/2 + B/2 = 20 or A+B= 40 ----(ii)
Substituting A+B= 40 from (ii) in (i), we get AB= 300
Now finding the factors of 300, whose sum is 40, we have 10 and 30
As B is more efficient than A, B can do the work in 10 days.
Question: 14 -
A supplies 20 men who work for 8 h per days for 6 days. B supplies 15 men working at 9 h per day for 7 day and C supplies 10 men working 6 h per day for 8 days to do a certain job. If ₹ 636 is paid for all the labour, what is C's share ?
-
₹ 128
-
₹ 136
-
₹ 148
-
₹ 154
Answer:
₹ 128
Solution:
Total man hours work done by men supplied by A, B and C
= (20 x 8 x 6), (15 x 9 x 7), (10 x 6 x 8)
and the wages must be in the ratio of the work done.
So, ₹ 636 has to divided among A, B and C in the ratio
= (20 x 8 x 6) : (15 x 9 x 7) : (10 x 6 x 8)
= 64 : 63 : 32
∴ C's share = (32/159) x 636
= ₹ 128
Total man hours work done by men supplied by A, B and C
= (20 x 8 x 6), (15 x 9 x 7), (10 x 6 x 8)
and the wages must be in the ratio of the work done.
So, ₹ 636 has to divided among A, B and C in the ratio
= (20 x 8 x 6) : (15 x 9 x 7) : (10 x 6 x 8)
= 64 : 63 : 32
∴ C's share = (32/159) x 636
= ₹ 128
Question: 15 -
3 men finish painting a wall in 8 days. Four boys do the same job in 7 days. In how many days will 2 men and 2 boys working together paint two such walls of the same size?
-
9(2/5) days
-
6(6/13) days
-
12(12/13) days
-
3(3/5) days
Answer:
12(12/13) days
Solution:
3men 8days =>1 man=1/24 days (1/3*1/8)
4boys 7days =>1 boy=1/28 days
2men+2boys =>2/24+2/28 =>1/12+1/14
2 such walls => 1/24+1/28
take LCM, 13/168
reciprocal of it, 168/13
i.e,12 12⁄13 days
3men 8days =>1 man=1/24 days (1/3*1/8)
4boys 7days =>1 boy=1/28 days
2men+2boys =>2/24+2/28 =>1/12+1/14
2 such walls => 1/24+1/28
take LCM, 13/168
reciprocal of it, 168/13
i.e,12 12⁄13 days