Question: 6 -
A system with transfer function 1/Ts+1, subjected to a step input takes to seconds to reach 50% of step height. The value of t is :
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20s
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6.9s
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14.4s
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10s
Answer:
14.4s
Solution:
A(t)=a[1-e-t/T] ½= 1-e-10/t
T= 14.43 sec.
A(t)=a[1-e-t/T] ½= 1-e-10/t
T= 14.43 sec.
Question: 7 -
The unit step response of an underdamped second order system has steady state value of -2 .Which one of the following transfer functions has these properties?
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-3.82/s2-1.91s+1.91
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-2.24/s2+2.59s+1.12
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-3.82/s2+1.91s+1.91
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-2.24/s2-2.59s+1.12
Answer:
-3.82/s2+1.91s+1.91
Solution:
Steady state Value = -2.
Denominator:
2ξωn = 1.91,
ωn = 1.4
ξ = 1.91/2ωn< 1…under damped
Steady state Value = -2.
Denominator:
2ξωn = 1.91,
ωn = 1.4
ξ = 1.91/2ωn< 1…under damped
Question: 8 -
A ramp input applied to an unity feedback system results in 5% steady state error. The type number and zero frequency gain of the system are respectively
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1 and 1/20
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0 and 1/20
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0 and 20
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1 and 20
Answer:
1 and 20
Solution:
ess = lims->0 sE(s), R(s) = 1/s2
= lims->0 s (R(s)/1+G(s))
ess = lims->0 sE(s), R(s) = 1/s2
= lims->0 s (R(s)/1+G(s))
Question: 9 -
A unit step is applied at t=0 to a first order system without time delay. The response has the value of 1.264 units at t=10 mins, and 2 units at steady state. The transfer function of the system is_____________
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2/(1+500s)
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3/(1+600s)
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5/(1+220s)
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2/(1+600s)
Answer:
2/(1+600s)
Solution:
a(t)= k[1-e-t/T] K=2
0.632= 1-e-10/T
T=600 sec
G(s)=2/(1+600s).
a(t)= k[1-e-t/T] K=2
0.632= 1-e-10/T
T=600 sec
G(s)=2/(1+600s).
Question: 10 -
First order system is defined as :
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Total number of poles and order of equation
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Total number of poles of equation
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Order of the differential equation
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Number of poles at origin
Answer:
Total number of poles and order of equation