Question: 11 -
The output in response to a unit step input for a particular continuous control system is c(t)= 1-e-t. What is the delay time Td?
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0.18
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0.36
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0.693
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0.289
Answer:
0.693
Solution:
Explanation: The output is given as a function of time. The final value of the output is limn->∞c(t)=1; . Hence Td (at 50% of the final value) is the solution of 0.5=1-e-Td, and is equal to ln 2 or 0.693 sec.
Explanation: The output is given as a function of time. The final value of the output is limn->∞c(t)=1; . Hence Td (at 50% of the final value) is the solution of 0.5=1-e-Td, and is equal to ln 2 or 0.693 sec.
Question: 12 -
Laplace transform of unit impulse signal is :
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A
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1/s
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1
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A/s
Answer:
1
Solution not available.
Question: 13 -
The damping ratio and peak overshoot are measures of:
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Speed of response
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Absolute stability
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Steady state error
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Relative stability
Answer:
Speed of response
Solution not available.
Question: 14 -
The forward path transfer function is given by G(s) = 2/s(s+3). Obtain an expression for unit step response of the system.
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1-2e-t+e+2t
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1-e-t+2e-2t
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1+e-t-2e-2t
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1+2e-t+e-2t
Answer:
1-2e-t+e+2t
Solution:
C(s)/R(s) = s/(s2+3s+2)
C(s) = 1/s-2/s+1+1/s+2
c(t) = 1-2e-t+e+2t.
C(s)/R(s) = s/(s2+3s+2)
C(s) = 1/s-2/s+1+1/s+2
c(t) = 1-2e-t+e+2t.
Question: 15 -
For the system 2/s+1, the approximate time taken for a step response to reach 98% of its final value is:
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8s
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2s
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1s
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4s
Answer:
4s
Solution:
C(s)/R(s) = 2/s+1
R(s) = 1/s (step input)
C(s) = 2/s(s+1)
c(t) = 2[1-e-t] 1.96 = 2[1-e-T] T= 4sec.
C(s)/R(s) = 2/s+1
R(s) = 1/s (step input)
C(s) = 2/s(s+1)
c(t) = 2[1-e-t] 1.96 = 2[1-e-T] T= 4sec.