Question: 6 -
A man can row his boat with the stream at 6 km/h and against the stream in 4 km/h. The man's rate is?
-
8
-
1
-
3
-
5
Answer:
1
Solution:
DS = 6
US = 4
S = ?
S = (6 - 4)/2 = 1 kmph
DS = 6
US = 4
S = ?
S = (6 - 4)/2 = 1 kmph
Question: 7 -
A man can row with a speed of 15 kmph in still water. If the stream flows at 5 kmph, then the speed in downstream is?
-
5
-
10
-
22
-
20
Answer:
20
Solution:
M = 15
S = 5
DS = 15 + 5 = 20
M = 15
S = 5
DS = 15 + 5 = 20
Question: 8 -
A man can swim in still water at 4.5 km/h, but takes twice as long to swim upstream than downstream. The speed of the stream is?
-
7.5
-
1.5
-
2.25
-
3
Answer:
1.5
Solution:
M = 4.5
S = x
DS = 4.5 + x
US = 4.5 + x
4.5 + x = (4.5 - x)2
4.5 + x = 9 -2x
3x = 4.5
x = 1.5
M = 4.5
S = x
DS = 4.5 + x
US = 4.5 + x
4.5 + x = (4.5 - x)2
4.5 + x = 9 -2x
3x = 4.5
x = 1.5
Question: 9 -
A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water?
-
1 hour
-
40 minutes
-
1 hr 15 min
-
1 hr 30 min
Answer:
1 hr 15 min
Solution:
Rate downstream =

1
x 60
km/hr = 6 km/hr.
10
Rate upstream = 2 km/hr.
Speed in still water =
1
(6 + 2) km/hr = 4 km/hr.
2
Required time =

5/4
hrs = 1
1
hrs = 1 hr 15 min.
Rate downstream = | ![]() |
1 | x 60 | ![]() |
10 |
Rate upstream = 2 km/hr.
Speed in still water = | 1 | (6 + 2) km/hr = 4 km/hr. |
2 |
![]() |
![]() |
5/4 | ![]() |
1 | hrs = 1 hr 15 min. |
Question: 10 -
Speed of a boat in standing water is 9 kmph and the speed of the stream is 1.5 kmph. A man rows to a place at a distance of 105 km and comes back to the starting point. The total time taken by him is:
-
16 hours
-
18 hours
-
20 hours
-
24 hours
Answer:
24 hours
Solution:
Speed upstream = 7.5 kmph.
Speed downstream = 10.5 kmph.
Total time taken =

105
+
105
hours = 24 hours.
7.5
10.5
Speed upstream = 7.5 kmph.
Speed downstream = 10.5 kmph.
Total time taken = | ![]() |
105 | + | 105 | ![]() |
7.5 | 10.5 |