Question: 11 -
The total number of events of throwing 10 coins simultaneously is
-
100
-
512
-
10
-
1024
Answer:
1024
Solution:
Total events 210 = 1024
Total events 210 = 1024
Question: 12 -
What will be the value of P(not E) if P(E) = 0.07?
-
72
-
93
-
007
-
90
Answer:
93
Solution:
If the probability of happening of an event P(E) and that of not happening is P(E), then
P(E) + P(not E) = 1
So, P(not E) = 1 - P(E)
Since P(E) = 0.07
P(not E) = 1 - 0.07
P(not E) = 0.93
If the probability of happening of an event P(E) and that of not happening is P(E), then
P(E) + P(not E) = 1
So, P(not E) = 1 - P(E)
Since P(E) = 0.07
P(not E) = 1 - 0.07
P(not E) = 0.93
Question: 13 -
A number is selected at random from first 50 natural numbers. Then the probability that it is a multiple of 3 and 4 is:
-
7/50
-
4/25
-
1/25
-
2/25
Answer:
2/25
Solution:
The numbers that are multiple of 3(from first 50 natural numbers) are:
3, 6, 9, 12, 15, 18………………..48
The numbers that are multiple of 4 (from first 50 natural numbers) are:
4, 8, 12, 16…………………….48
The numbers that are multiples of 3 and 4 both are the multiples of 3×4=12 as both 3 and 4 are co-prime.
So common multiples are:
12, 24, 36, 48
Therefore probability is:
P (multiple of 3 and 4) = 4/50
⇒ P (multiple of 3 and 4) = 2/25
The numbers that are multiple of 3(from first 50 natural numbers) are:
3, 6, 9, 12, 15, 18………………..48
The numbers that are multiple of 4 (from first 50 natural numbers) are:
4, 8, 12, 16…………………….48
The numbers that are multiples of 3 and 4 both are the multiples of 3×4=12 as both 3 and 4 are co-prime.
So common multiples are:
12, 24, 36, 48
Therefore probability is:
P (multiple of 3 and 4) = 4/50
⇒ P (multiple of 3 and 4) = 2/25
Question: 14 -
Cards bearing numbers 3 to 20 are placed in a bag and mixed thoroughly. A card is taken out from the bag at random. The probability that the number on the card taken out is an even number, is
-
1/3
-
1/20
-
1/4
-
1/2
Answer:
1/2
Solution:
Total cards = 18
Cards with even numbers are 4, 6, 8, 10, 12, 14, 16, 18, 20 = 9
∴ P(even number) =918=12
Total cards = 18
Cards with even numbers are 4, 6, 8, 10, 12, 14, 16, 18, 20 = 9
∴ P(even number) =918=12
Question: 15 -
A number x is chosen at random from the numbers -2, -1, 0 , 1, 2. Then the probability that x2 < 2 is?
-
4/5
-
2/5
-
1/5
-
3/5
Answer:
3/5
Solution:
We have 5 numbers −2,−1,0,1,2
Whose squares are 4,1,0,1,4
So square of 3 numbers is less than 2
Therefore Probability is:
P (x2 < 2) = 3/5
We have 5 numbers −2,−1,0,1,2
Whose squares are 4,1,0,1,4
So square of 3 numbers is less than 2
Therefore Probability is:
P (x2 < 2) = 3/5