Question: 26 -
There are 3 red balls, 4 green balls, and 5 black balls in a basket. The probability of not getting the red balls is
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3/4
-
1/4
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5/12
-
1/3
Answer:
3/4
Solution:
Total number of balls all together = 3 + 4 + 5 = 12
Total number of red balls = 3
Total number of green balls = 4
Total number of black balls = 5
Now, the total number of non-red balls = 9
P (E) = Total number of non-red balls/Total number of balls
= 9/12 = 3/4.
Hence, the total number of non-red balls is 3/4.
Total number of balls all together = 3 + 4 + 5 = 12
Total number of red balls = 3
Total number of green balls = 4
Total number of black balls = 5
Now, the total number of non-red balls = 9
P (E) = Total number of non-red balls/Total number of balls
= 9/12 = 3/4.
Hence, the total number of non-red balls is 3/4.
Question: 27 -
Find out the probability of a selected number is a multiple of 3 from the numbers 1, 2, 3, 4, 5, 6, ……14, 15, 16, 17, 18.
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5/13
-
1/6
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1/5
-
1/3
Answer:
1/3
Solution:
Sample Space = 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18
Multiples of 3 from the sample space = 3, 6, 9, 12, 15, 18
P (E) = Number multiple of 3/Total numbers given in the sample space
= 6/18 = 1/3
Hence, a multiple of 3 from the numbers is 1/3.
Sample Space = 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18
Multiples of 3 from the sample space = 3, 6, 9, 12, 15, 18
P (E) = Number multiple of 3/Total numbers given in the sample space
= 6/18 = 1/3
Hence, a multiple of 3 from the numbers is 1/3.