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Quiz: Problem on Ages

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Number of Questions: 21

Question: 11 -

The ratio of the ages of Seeta and Geeta is 2:7. After 6 years, the ratio of their ages will be 1:2. What is the difference in their present ages?

Options:

  1. 9 years

  2. 11 years

  3. 10 years

  4. 8 years

    5. Answer:

    10 years
    Solution:

    Let the age of Seeta is 2X and age of Geeta 7X.

    As per question after 6 years;

    Apti Problem on ages 16

    4X +12 = 7X + 6

    -3X = -6

    X = 2

    ∴Age of Seeta = 2 * 2 = 4 years

    Age of Geeta = 7 * 2 = 14 years

    Difference in their ages = 14 - 4 = 10 years

Question: 12 -

Four years ago a man was 6 times as old as his son. After 16 years he will be twice as old as his son. What is the present age of man and his son?

Options:

  1. 34, 9

  2. 33, 7

  3. 36, 6

  4. 35, 5

    5. Answer:

    34, 9
    Solution:

    Let age of son 4 years ago be = X

    So, age of man 4 years ago would be = 6X

    As per question after 16 years;

    2* age of son = age of man

    2(X + 4 +16) = (6X + 4 + 16)

    2X +40 = 6X + 20

    2X - 6X = 20 - 40

    - 4X = - 20

    X = 5 years

    ∴Present age of son = 5 + 4= 9 years

    Present age of man = 6X + 4= 6*5 + 4 = 30 +4 = 34 years

Question: 13 -

The ratio of the ages of Minu and Meera is 4:2. If the sum of their ages is 6 years, find the ratio of their ages after 8 years.

Options:

  1. 7:5

  2. 8:6

  3. 6:5

  4. 6:4

    5. Answer:

    6:5
    Solution:

    Let the age of Minu is 4X and age of Meera 2X.

    As per question; 4X + 2X = 6

    6X = 6

    X = 1

    ∴Minu's age = 4*1= 4 years

    Meera's age = 2*1= 2 years

    Ratio of their ages after 8 years;

    = (4+8): (2+8)

    = 12: 10

    = 6:5

Question: 14 -

Ten years ago, the sum of ages of a father and his son was 34 years. If the ratio of present ages of the father and son is 7:2, find the present age of the son.

Options:

  1. 12 years

  2. 8 years

  3. 11 years

  4. 10 years

    5. Answer:

    12 years
    Solution:

    Let the present age of the father is 7X and present age of son is 2X.

    As per question, ten years ago;

    (7X - 10)+ (2X - 10) = 34

    7X - 10 + 2X - 10= 34

    9X = 34 + 20

    9X = 54

    X = 6

    ∴Present age of son = 2 * 6= 12 years

Question: 15 -

A mother is twice as old as her son. If 20 years ago, the age of the mother was 10 times the age of the son, what is the present age of the mother?

Options:

  1. 40 year

  2. 38 year

  3. 45 year

  4. 43 year

    5. Answer:

    45 year
    Solution:

    Let the age of son = X years

    ∴Age of mother would be =2X

    As per question 20 years ago;

    10 (X -20) = 2X - 20

    10X - 200 = 2X - 20

    10X - 2X= - 20 + 200

    8X = 180

    X=Apti Problem on ages 13= 22.5 years

    ∴Age of mother = 22.5 * 2 = 45 years