Question: 16 -
Simran is younger than Simarjeet by 7 years, and the ratio of their ages is 7:9. What is the age of Simran?
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23.5 years
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25 years
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24.5 years
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24 years
Answer:
24.5 years
Solution:
Let the age of Simran and Simarjeet be 7x and 9x respectively
According to the Question-
7x=9x-7
x=7/2=3.5
So, Simran's age =7x=7×3.5=24.5 years.
Let the age of Simran and Simarjeet be 7x and 9x respectively
According to the Question-
7x=9x-7
x=7/2=3.5
So, Simran's age =7x=7×3.5=24.5 years.
Question: 17 -
The sum of the ages of father and his son is 44 years. If 6 years after the father will be 3 times as old as his son, what are their present ages?
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38, 6
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37, 7
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35, 9
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36, 8
Answer:
36, 8
Solution:
Let present age of son is X and present age of father is (44 -X).
As per question, after 6 years;
3(X+6) = (44 - X) +6
3X +18 = 50 - X
4X = 50 - 18
4X = 32
X = 8 years
∴Present age of son = 8 years
And, present of father = 44 - 8 = 36 years
Let present age of son is X and present age of father is (44 -X).
As per question, after 6 years;
3(X+6) = (44 - X) +6
3X +18 = 50 - X
4X = 50 - 18
4X = 32
X = 8 years
∴Present age of son = 8 years
And, present of father = 44 - 8 = 36 years
Question: 18 -
The present ages of Arun, Sunil, and Vivek are in proportions 4:7:9. Before eight years, the sum of their ages was 56. What are their present ages in years?
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Insufficient Data
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16,28,36
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16,28,40
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16,30,40
Answer:
16,28,36
Solution:
Let the ratio constant be x
Then the Present age of Arun, Sunil and Vivek would be 4x, 7x, 9x
Age before eight years:
4x-8, 7x-8, 9x-8
According to question
4x-8 + 7x-8 + 9x-8 = 56
20x = 80
x= 80/20
x= 4
Then their present is 4×4 = 16; 7×4= 28 and 9×4= 36 respectively.
Let the ratio constant be x
Then the Present age of Arun, Sunil and Vivek would be 4x, 7x, 9x
Age before eight years:
4x-8, 7x-8, 9x-8
According to question
4x-8 + 7x-8 + 9x-8 = 56
20x = 80
x= 80/20
x= 4
Then their present is 4×4 = 16; 7×4= 28 and 9×4= 36 respectively.
Question: 19 -
The sum of the present age of mother and her son is 60 years. Six years ago, the age of the mother was five times the age of her son. What will be the age of her son after 6 years?
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20 years
-
21 years
-
23 years
-
22 years
Answer:
20 years
Solution:
Let the present age of the son =x
Then, the present age of the mother =(60-x)
As per question:
Six years ago mother's age was 5 times the age of her son:
So, (60-x) -6=5(x-6)
54 - x = 5x -30
84=6x
x=84/6
x=14 Years
Age of son after 6 years
=x+6
=14+6
=20 Years
Let the present age of the son =x
Then, the present age of the mother =(60-x)
As per question:
Six years ago mother's age was 5 times the age of her son:
So, (60-x) -6=5(x-6)
54 - x = 5x -30
84=6x
x=84/6
x=14 Years
Age of son after 6 years
=x+6
=14+6
=20 Years
Question: 20 -
Age of father is seven times the age of his son. In the next 10 years, the age of father will be three times the age of his son. What is the age of father now?
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39 years
-
41 years
-
37 years
-
35 years
Answer:
35 years
Solution:
Let the age of son is X and age of father 7X
Age of son after 10 years = X+10
Age of father after 10 years = 7X + 10
As per question, after 10 years;
3(X+10) = 7X + 10
3X + 30 = 7X + 10
4X = 20
X = 5 years
∴Age of father now = 7 * 5 = 35 years
Let the age of son is X and age of father 7X
Age of son after 10 years = X+10
Age of father after 10 years = 7X + 10
As per question, after 10 years;
3(X+10) = 7X + 10
3X + 30 = 7X + 10
4X = 20
X = 5 years
∴Age of father now = 7 * 5 = 35 years