Quiz: EDC-Semiconductor Theory

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Number of Questions: 20

Question: 16 -

The intrinsic carrier density at 300K is 1.5 * 1010/cm3 , in silicon for n-type silicon doped to 2.25*10^15 atoms/cm3 , the equilibrium electron and hole densities are

Options:
  1. n = 1.5 * 1010/cm3, p=1.5*1010/cm3

  2. n = 1.5 * 1010/cm3, p=2.25*1015/cm3

  3. n = 1.5 * 1015/cm3, p=1.5*1010/cm3

  4. n = 2.25 * 1015/cm3, p=1.0*105/cm3

  5. Answer:

    n = 2.25 * 1015/cm3, p=1.0*105/cm3

    Solution not available.

Question: 17 -

According to the Einstein relation , for any semiconductor the ratio of diffusion constant to mobility of carriers:

Options:
  1. Is a universal constant

  2. Varies with life time of the semiconductor

  3. Depends upon the temperature of the semiconductor

  4. Depends upon the type of the semiconductor

  5. Answer:

    Depends upon the temperature of the semiconductor

    Solution not available.

Question: 18 -

Direct band gap semi conductors

Options:
  1. Exhibit short carrier life time and they are used for fabricating BJT's

  2. Exhibit long carrier life time and they are used for fabricating lasers

  3. Exhibit short carrier life time and they are used for fabricating lasers

  4. Exhibit long carrier life time and they are used for fabricating BJT's

  5. Answer:

    Exhibit short carrier life time and they are used for fabricating lasers

    Solution not available.

Question: 19 -

A silicon Sample is uniformly doped with 1016phosphorous atoms / cm3 and 2 * 1016 boron atoms / cm3 If all the dopants are fully ionized , the material is

Options:
  1. p-type with carrier concentration of 2*1016/cm3

  2. n-type with carrier concentration of 1016/cm3

  3. p-type with carrier concentration of 1016/cm3

  4. n-type with carrier concentration of 2*1016/cm3

  5. Answer:

    p-type with carrier concentration of 1016/cm3

    Solution not available.

Question: 20 -

In a p-type semiconductor , the fermi level lies 0.39 ev above the valence band . Determine the new position of the fermi level if the concentration of acceptor atoms is tripled . Assume KT = 26 mV

Options:
  1. 0.36 eV

  2. 0.40 eV

  3. No change

  4. 0.44 eV

  5. Answer:

    0.36 eV

    Solution not available.