Question: 6 -
The price of a car is Rs. 3,25,000. It was insured to 85% of its price. The car was damaged completely in an accident and the insurance company paid 90% of the insurance. What was the difference between the price of the car and the amount received?
-
Rs.70,000
-
Rs.76,375
-
Rs.82,150
-
Rs.34,000
Answer:
Rs.76,375
Solution:
Price of the car = Rs.3,25,000
Car was insured to 85% of its price
Insured price =325000×(85/100)
Insurance company paid 90% of the insurance.
Amount paid by insurance company
=325000×(85/100)×(90/100)=325×85×9=248625
Difference between the price of the car and the amount received
=325000−248625= Rs.76375
Price of the car = Rs.3,25,000
Car was insured to 85% of its price
Insured price =325000×(85/100)
Insurance company paid 90% of the insurance.
Amount paid by insurance company
=325000×(85/100)×(90/100)=325×85×9=248625
Difference between the price of the car and the amount received
=325000−248625= Rs.76375
Question: 7 -
A student has to obtain 33% of the total marks to pass. He got 125 marks and failed by 40 marks. The maximum mark is
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500
-
300
-
600
-
400
Answer:
500
Solution:
The student got 125 marks and still failed by 40 marks.
=> mark required to pass =125+40=165
Therefore, 33% of the total marks =165
=> 100% of the total marks =(165×100)/33=500
i.e., maximum mark = 500
The student got 125 marks and still failed by 40 marks.
=> mark required to pass =125+40=165
Therefore, 33% of the total marks =165
=> 100% of the total marks =(165×100)/33=500
i.e., maximum mark = 500
Question: 8 -
If the price of petrol increases by 25% and Benson intends to spend only an additional 15% on petrol, by how much percent will he reduce the quantity of petrol purchased?
-
8%
-
6%
-
7%
-
10%
Answer:
8%
Solution:
Assume that initial price of 1 litre petrol = Rs.100,
Benson spends Rs.100 for petrol such that he buys 1 litre of petrol.
After the increase by 25%, price of 1 litre petrol=100+25=125
Since Benson spends additional 15% on petrol, amount spent by him=100+15=115
Hence quantity of petrol that he can purchase=115/125 litre
Quantity of petrol reduced
=(1−115/125)=10/125 litre
Required reduction percent
=(10/125)×100=(10/125)×100=(10/5)×4=2×4=8%
Assume that initial price of 1 litre petrol = Rs.100,
Benson spends Rs.100 for petrol such that he buys 1 litre of petrol.
After the increase by 25%, price of 1 litre petrol=100+25=125
Since Benson spends additional 15% on petrol, amount spent by him=100+15=115
Hence quantity of petrol that he can purchase=115/125 litre
Quantity of petrol reduced
=(1−115/125)=10/125 litre
Required reduction percent
=(10/125)×100=(10/125)×100=(10/5)×4=2×4=8%
Question: 9 -
30% of the men are more than 25 years old and 80% of the men are less than or equal to 50 years old. 20% of all men play football. If 20% of the men above the age of 50 play football, what percentage of the football players are less than or equal to 50 years?
-
70%
-
80%
-
90%
-
60%
Answer:
80%
Solution:
Let total number of men = 100
Then,20 men play football.
80 men are less than or equal to 50 years old.
Remaining 20 men are above 50 years old.
Number of football players above 50 years old=20×(20/100)=4
Number of football players less than or equal to 50 years old=20−4=16
Required percentage
=(16/20)×100=80%
Let total number of men = 100
Then,20 men play football.
80 men are less than or equal to 50 years old.
Remaining 20 men are above 50 years old.
Number of football players above 50 years old=20×(20/100)=4
Number of football players less than or equal to 50 years old=20−4=16
Required percentage
=(16/20)×100=80%
Question: 10 -
On my sister's 15th birthday, her height was 159 cm, having grown 6% since the year before. How tall was she in the previous year?
-
142 cm
-
150 cm
-
154 cm
-
140 cm
Answer:
150 cm
Solution:
Given that height on 15th birthday = 159 cm,
growth = 6%
Let height in the previous year =x
Then height on 15th birthday =x×(106/100)
x×(106/100)=159⇒x=(159×100)/106=1.5×100=150 cm
Given that height on 15th birthday = 159 cm,
growth = 6%
Let height in the previous year =x
Then height on 15th birthday =x×(106/100)
x×(106/100)=159⇒x=(159×100)/106=1.5×100=150 cm