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Quiz: Percentage

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Number of Questions: 44

Question: 26 -

In a group of 80 children and 10 youngsters, each child got sweets that are 15% of the total number of children and each youngster got sweets that are 25% of the total number of children. How many sweets were there? 

Options:

  1. 1100

  2. 1080

  3. 1160

  4. 1210

    5. Answer:

    1160
    Solution:

    Number of sweets each child got = 15% of 80 = 15/100 * 80 = 12.
    Number of sweets 80 children got = 80 * 12 = 960.
    Number of sweets each youngster got = 25% of 80 = 25/100 * 80 = 20.
    Number of sweets 10 youngsters got = 10 * 20 = 200.
    Total number of sweets = 960 + 200 = 1160.

Question: 27 -

There is a 30% increase in the price of an article in the first year, a 20% decrease in the second year and a 10% increase in the next year. If the final price of the article is Rs. 2288, then what was the price of the article initially? 

Options:

  1. Rs. 2400

  2. Rs. 1800

  3. Rs. 2000

  4. Rs. 1500

    5. Answer:

    Rs. 2000
    Solution:

    Let the price of the article, four years age be Rs. 100 in the 1st year, price of the article = 100 + 30 = Rs. 130. In the 2nd year, price = 130 - 20% of 130 = 130 - 26 = Rs. 104. 
    In the 3rd year, price = 104 + 10% of 104 = 104 + 10.4 = Rs. 114.40.
    But present price of the article is Rs. 2288
    for 114.4 ---> 100 ; 2288 ---> ?
    Required price = (2288 * 100)/114.4 = 20 * 100 = Rs. 2000.

Question: 28 -

A man donated 5 % of his income to a charitable organization and deposited 20 % of the remainder in a bank. If he now has Rs. 1919 left, what is his income? 

Options:

  1. Rs. 2300

  2. Rs. 2500

  3. Rs. 2525

  4. Rs. 2558

    5. Answer:

    Rs. 2525
    Solution:

    Let his income be Rs. x. 
    Then X – 5 % of x – 20 % of 95 % of x = 1919 
    or x – x/20 – (20×95×x)/(100 × 100) = 1919 
    or x – x/20 - 19x/100 = 1919 
    or 100x – 5x – 19x = 191900 
     X = 191900/76= 2525

Question: 29 -

Two tests had the same maximum mark. The pass percentages in the first and the second test were 40% and 45% respectively. A candidate scored 216 marks in the second test and failed by 36 marks in that test. Find the pass mark in the first test? 

Options:

  1. 224

  2. 136

  3. 128

  4. 164

    5. Answer:

    224
    Solution:

    Let the maximum mark in each test be M.
    The candidate failed by 36 marks in the second test.
    pass mark in the second test = 216 + 36 = 252
    45/100 M = 252
    Pass mark in the first test = 40/100 M = 40/45 * 252 = 224.

Question: 30 -

There are two numbers. If 40% of the first number is added to the second number, then the second number increases to its five-fourth. Find the ratio of the first number to the second number? 

Options:

  1. 8 : 25

  2. 5 : 8

  3. 25 : 8

  4. 8 : 5

    5. Answer:

    5 : 8
    Solution:

    Let the two numbers be x and y.
    40/100 * x + y = 5/4y
    => 2/5 x = 1/4 y => x/y = 5/8