Quiz: Percentage

To View Tricks: Login Required

Number of Questions: 44

Question: 41 -

In a factory there are three types of Machines M1 , M2 and M3 which produces 25%, 35% and 40% of the total products respectively. M1, M2 and M3 produces 2% , 4% and 5% defective products, respectively. What is the percentage of non-defective products?

Options:
  1. 89%

  2. 96.1%

  3. 97%

  4. 86.1%

  5. Answer:

    96.1%

    Solution:

    Non- defective products

    {(25x0.98+35x0.96+40x0.95)/100} x 100 = 96.1


Question: 42 -

In measuring the sides of a rectangle errors of 5 % and 3 % in excess are made. The error percent in the calculates area is 

Options:
  1. 8.15%

  2. 8. 35 %

  3. 7.15%

  4. 6. 25%

  5. Answer:

    8.15%

    Solution:

    Let length = x units and breadth = Y units 
    Then actual area = xy sq.units 
    Length shown = (105/100 × x)units = 21x/20 units; 
    Breadth shown = (103/100 × Y) 
    Calculated area = (21x/20 × 103y/100)sq.units 
    = 2163xy/2000 sq.units 
    Error = (2163xy/2000 - xy) 
    = 163xy/2000 
    Error % = (163xy/2000 × 1/xy × 100)% 
    = 163/20 % = 8.15 % 


Question: 43 -

Fresh grapes contain 80 % water dry grapes contain 10 % water. If the weight of dry grapes is 250 kg. What was its total weight when it was fresh? 

Options:
  1. 1225kg

  2. 1000kg

  3. 1125kg

  4. 1100kg

  5. Answer:

    1125kg

    Solution:

    Let the weight of fresh grapes be x kg 
    Quantity of water in it = (80/100 × x)kg = 4x/5 kg 
    Quantity of pulp in it = (x – 4x/5)kg = x/5 kg 
    Quantity of water in 250 kg dry grapes 
    = (10/100 × 250)kg = 25kg 
    Quantity of pulp in it = (250 - 25)kg = 225 kg 
    Therefore, x/5 = 225 
    => x = 1125 


Question: 44 -

The average of a set of whole numbers is 27.2. when the 20% of the elements are eliminated from the set of numbers then the average become 34. The number of elements in the new set of numbers can be :

Options:
  1. 27

  2. 63

  3. 35

  4. 52

  5. Answer:

    52

    Solution:

    only (c) is correct since it is divisible by 4.
    Let the original number of element  be x then the new no.of elements will be 
                4x/5 = K                               
    So K must be divisible by 4
    Since,      x =  Kx5/4