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Quiz: Perimeter and Area

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Number of Questions: 31

Question: 16 -

If the size of a tile is 9" by 9", how many tiles are required to cover a 12 ft. wide and 18 ft. long floor?

Options:

  1. 216

  2. 32

  3. 24

  4. 384

    5. Answer:

    384
    Solution:

    Area Aptitude

Question: 17 -

The sides of a rectangular field are in the ratio 3: 4 and its area is 7500 m2. What is the cost of fencing it at 25 paise per meter?

Options:

  1. Rs. 57.50

  2. Rs. 67.50

  3. Rs. 87.50

  4. Rs. 77.50

    5. Answer:

    Rs. 87.50
    Solution:

    Ratio between the sides of rectangle = 3: 4

       Let the ratio constant be x then,

       Length = 3x and breadth = 4x

       Area = L x B

                  7500=3x × 4x=12x2
                  Area Aptitude= x2=625

                    x=25

    Length = 3 x 25 = 75 m, and Breadth = 4 x 25 = 100 m

    Perimeter = 2(75 + 100) = 2 x 175 = 350 m

    Cost of fencing 1 meter = 25 paise

    Cost of fencing 350 m = 350 x 25 = 8750 paise

    In rupees: Rs. 87.50

Question: 18 -

The difference between the length and the perimeter of a rectangle is 100 cms. What is the breadth of the rectangle?

Options:

  1. 60 cms

  2. 80 cms

  3. Data Inadequate

  4. 100 cms

    5. Answer:

    Data Inadequate
    Solution:

    Let the length of the rectangle be 'x' and breadth of the rectangle be 'y'

    According to the question:

    2(x + y) - x = 100

    2x + 2y - x = 100

    x + 2y = 100

    From this we cannot find 'y' (breadth), so the given data is inadequate.

Question: 19 -

If each side of the square is increased by 50%, what will be the ratio between the new area and the original area of the square?

Options:

  1. 9: 4

  2. 5: 4

  3. 4: 5

  4. 4: 9

    5. Answer:

    9: 4
    Solution:

    Area Aptitude

Question: 20 -

The sides of a rhombus are 10 cm in length, and one diagonal is 16 cm. The area of the rhombus is

Options:

  1. 94 cm2

  2. 95 cm2

  3. 93 cm2

  4. 96 cm2

    5. Answer:

    96 cm2
    Solution:

    When d1 and d2 are the diagonals of rhombus then,
    The Side of rhombus = Area Aptitude

    Area Aptitude

    Squaring both sides

    202 = 162 + d22

    400 = 256 + d22

    d22 = 400 - 256

    d2 = √144

    d2 = 12

    Area of rhombus =1/2( d1 × d2 )

          =1/2 ( 16 × 12 )=96 cm2