Question: 1 -
Two coins are thrown at the same time. Find the probability of getting both heads.
-
3/4
-
0
-
1/4
-
1/2
Answer:
1/4
Solution:
Since two coins are tossed, therefore total number of cases = 22 = 4
Therefore, probability of getting heads in both coins is:
∴ P (head) = 1/4
Since two coins are tossed, therefore total number of cases = 22 = 4
Therefore, probability of getting heads in both coins is:
∴ P (head) = 1/4
Question: 2 -
A dice is thrown. Find the probability of getting an even number.
-
1
-
2/3
-
5/6
-
1/2
Answer:
1/2
Solution:
Total number of cases = 6 (1,2,3,4,5,6)
There are three even numbers 2,4,6
Therefore probability of getting an even number is:
P (even) = 3/6
⇒ P (even) = 1/2
Total number of cases = 6 (1,2,3,4,5,6)
There are three even numbers 2,4,6
Therefore probability of getting an even number is:
P (even) = 3/6
⇒ P (even) = 1/2
Question: 3 -
A bag contains 5 red balls and some blue balls .If the probability of drawing a blue ball is double that of a red ball, then the number of blue balls in a bag is:
-
20
-
10
-
15
-
5
Answer:
10
Solution:
Let the number of blue balls be x
Then total number of balls will be 5 + x.
According to question,
x/(5 + x) = 2 X (5/5+x)
⇒ x = 10
Let the number of blue balls be x
Then total number of balls will be 5 + x.
According to question,
x/(5 + x) = 2 X (5/5+x)
⇒ x = 10
Question: 4 -
Two dice are thrown simultaneously. The probability of getting a sum of 9 is:
-
1/9
-
1/10
-
4/9
-
3/10
Answer:
1/9
Solution:
Total cases = 36
Total cases in which sum of 9 can be obtained are:
(5, 4), (4, 5), (6, 3), (3, 6)
∴ P (9) = 4/36 = 1/9
Total cases = 36
Total cases in which sum of 9 can be obtained are:
(5, 4), (4, 5), (6, 3), (3, 6)
∴ P (9) = 4/36 = 1/9
Question: 5 -
100 cards are numbered from 1 to 100. Find the probability of getting a prime number.
-
3/4
-
1/4
-
29/100
-
27/50
Answer:
1/4
Solution:
Total prime numbers from 1 to 100 are:
2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97
That means 25 out of 100
So probability is:
P (prime) = 25/100
⇒ P (prime) = 1/4
Total prime numbers from 1 to 100 are:
2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97
That means 25 out of 100
So probability is:
P (prime) = 25/100
⇒ P (prime) = 1/4