Question: 1 -
The base of a right-angled triangle is 10 and hypotenuse is 20. What is its area?
-
58 meters
-
52 meters
-
68 meters
-
60 meters
Answer:
60 meters
Solution:
The area of a right angled triangle = ½ * base * height
Base = 10, Hypotenuse = 20
Height2 = Hypotenuse2 - Base2
= 202 - 162
= 400 - 256
Height2 = 144
Height = 12
Area = ½ * base * height
= ½ * 10 * 12
= 60 meters
The area of a right angled triangle = ½ * base * height
Base = 10, Hypotenuse = 20
Height2 = Hypotenuse2 - Base2
= 202 - 162
= 400 - 256
Height2 = 144
Height = 12
Area = ½ * base * height
= ½ * 10 * 12
= 60 meters
Question: 2 -
The perimeter of the rectangular field is 480 meters and the ratio between the length and breadth is 5:3. Find the area of the field.
-
54000 m2
-
7200 m2
-
15000 m2
-
13500 m2
Answer:
13500 m2
Solution:
Let the length of the rectangle be 5x, and breadth be 3x,
Perimeter of a rectangle = 2(l +b) = 480
2(5x + 3x) = 480
2 x 8x = 480
16x = 480
x = 480/16 = 30
∴ Length = 5 x 30 = 150 m
Breadth = 3 x 30 = 90 m
And, Area of rectangle = L x B
= 150 x 90 = 13500 m2
Let the length of the rectangle be 5x, and breadth be 3x,
Perimeter of a rectangle = 2(l +b) = 480
2(5x + 3x) = 480
2 x 8x = 480
16x = 480
x = 480/16 = 30
∴ Length = 5 x 30 = 150 m
Breadth = 3 x 30 = 90 m
And, Area of rectangle = L x B
= 150 x 90 = 13500 m2
Question: 3 -
The ratio of length and breadth of a rectangular park is 4:2. If a cat running along the boundary of the park at the speed of 18 km/hr completes one round in 10 minutes, find the area of the park in square meters.
-
68000 sq. m
-
50000 sq. m
-
45000 sq. m
-
55000 sq. m
Answer:
50000 sq. m
Solution:
One round of the park is equal to the perimeter of the park.
So, by completing one round, the cat covers a distance equal to the perimeter of the park.
Now, Distance or perimeter = speed * time
= 18 * (10/60)
= 3 km or 3000 meters
Let Length = 4x and breadth = 2x
So, Perimeter: 2 (4x + 2x) = 3000
8x + 4x = 3000
12x = 3000
x= 3000/12= 250 meters
So, Length = 4 * 250 = 1000 meters
And, Breadth = 2 * 250 = 500 meters
Area = Length * Breadth
= 1000 * 500
= 50000 sq. m.
One round of the park is equal to the perimeter of the park.
So, by completing one round, the cat covers a distance equal to the perimeter of the park.
Now, Distance or perimeter = speed * time
= 18 * (10/60)
= 3 km or 3000 meters
Let Length = 4x and breadth = 2x
So, Perimeter: 2 (4x + 2x) = 3000
8x + 4x = 3000
12x = 3000
x= 3000/12= 250 meters
So, Length = 4 * 250 = 1000 meters
And, Breadth = 2 * 250 = 500 meters
Area = Length * Breadth
= 1000 * 500
= 50000 sq. m.
Question: 4 -
The sides of a triangle are in the ratio 10: 24:26 and its perimeter is 300 m. What is its area?
-
3000 m2
-
4000 m2
-
2500 m2
-
3500 m2
Answer:
2500 m2
Solution:
Let the sides are 10x, 24x, and 26x.
The perimeter is 300 m.
So, 10x + 24x + 26x = 300
60x = 300
x= 5
So, the sides are 10 *5 = 50 meters
24 * 5 = 100 meters
26 * 5 = 130 meters
102 + 242 = 262 so, it is a right triangle.
100 + 576 = 676
The area of a right triangle is = 1/2 * base * height
= 1/2 * 50 * 100
= 2500 m2
Let the sides are 10x, 24x, and 26x.
The perimeter is 300 m.
So, 10x + 24x + 26x = 300
60x = 300
x= 5
So, the sides are 10 *5 = 50 meters
24 * 5 = 100 meters
26 * 5 = 130 meters
102 + 242 = 262 so, it is a right triangle.
100 + 576 = 676
The area of a right triangle is = 1/2 * base * height
= 1/2 * 50 * 100
= 2500 m2
Question: 5 -
What is the area of a triangle with base 5 meters and height 10 meters?
-
40 square meters
-
20 square meters
-
35 square meters
-
25 square meters
Answer:
25 square meters
Solution:
Area of a triangle = ½ * base * height
So, the area = ½* 5 * 10
=25 square meters
Area of a triangle = ½ * base * height
So, the area = ½* 5 * 10
=25 square meters